$\dfrac{(\dfrac{-8}{3})}{(\dfrac{-3}{4})}$=

$(\dfrac{-3}{4})+(\dfrac{-9}{2})$=

$(\dfrac{-3}{2})-\dfrac{2}{9}$=

$(\dfrac{-1}{3})-(\dfrac{-2}{3})$=

$(\dfrac{-5}{8}) : \dfrac{6}{7}$=

$\dfrac{7}{3}\times\dfrac{7}{4}$=

$\dfrac{7}{9}\times(\dfrac{-2}{3})$=

$(\dfrac{-2}{5})\times\dfrac{8}{5}$=

$\dfrac{1}{3} : (\dfrac{-8}{7})$=

$(\dfrac{-4}{3})+\dfrac{3}{2}$=