$\dfrac{(\dfrac{-6}{7})}{\dfrac{7}{6}}$=

$\dfrac{4}{9}-\dfrac{7}{3}$=

$\dfrac{3}{2}-(\dfrac{-4}{9})$=

$(\dfrac{-6}{5})\times\dfrac{8}{3}$=

$\dfrac{\dfrac{3}{7}}{(\dfrac{-4}{3})}$=

$\dfrac{9}{8}+\dfrac{7}{8}$=

$(\dfrac{-7}{3})-(\dfrac{-3}{4})$=

$\dfrac{1}{4}\times\dfrac{5}{9}$=

$\dfrac{(\dfrac{-1}{2})}{(\dfrac{-5}{2})}$=

$\dfrac{9}{4}+\dfrac{2}{3}$=